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@ -96,7 +96,7 @@ $$
The velocity of the wall will take the following form:
$$
v_w' = \lim\limits_{m_w \to \infty} \frac{2m_1v_1 + v_w(m_w-m_1)}{m+m_w} = \lim\limits_{m_w \to \infty} \frac{2m_1v_1}{m+m_w} = 0
v_w' = \lim\limits_{m_w \to \infty} \frac{2mv + v_w(m_w-m)}{m+m_w} = \lim\limits_{m_w \to \infty} \frac{2mv}{m+m_w} = 0
$$
This leads to the conclusion that the wall will not change its position, but the particle will change its velocity value to the opposite.